A flint glass and a crown glass are fitted on the two slits of a double slit apparatus. The thickness of the strips is 0.40 mm and the separation between the slits is 0.12 cm. The refractive index of flint glass and crown glass are 1.62 and 1.52 respectively for the light of wavelength 480 nm which is used in the experiment.The interference is observed on a screen a distance one meter away.
(a) What would be the fringe-width?
(b) At what distance from the geometrical centre will the nearest maximum be located?

Find the thickness of a plate which will produce a change in optical path equal to one fourth of the wavelength λ of the light passing through it normally. The refractive index of the plate is µ.

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Since after passing through the two materials wave length of light will remain same and value of D and d will als remain sameand fringe width β is given by:β=λDdhence fringe width will remain same.now fringe shift from the centre due to the upper slitis y1=βλμ-1t this is for flinty1=Ddμ-1t=1000.121.62-1×0.4 mm=206.66 mmthis shift is towards upwardnow fringe shift from the centre due to the lower slitis y1=βλμ-1t this is for crowny1=Ddμ-1t=1000.121.52-1×0.4 mm=173.33 mmthis shift is towards downwardso net fringe shifty = 206.66-173.33=33.33 mm upward from the centre.

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