a force acting on a particle of mass 200g displaces it through 400cm in 2s. find the magnitude of force if the initial velocity of the particle is zero

If the initial velocity of the particle is zero then acceleration isa=2st2Here s=400 cm=4 m and t=2 s. So we havea=2×422=2Now mass m=200 g = 0.2 kg. So force f=ma=0.2×2=0.4 N

  • 4
u = 0
t = 2s
m = 200g = 0.5 kg
s= 400cm= 4 m
s= ut + 1/2× at^2
4 = 0 + 1/2 × a × 2×2
4= 2a
a = 2 m/s^2
F = ma
F = 0.5 kg × 2 m/s^2
F = 1 N
  • -5
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