a friendly cricket match is organized between 2 teams . the money got will be given to a charitable hospital.The field is circular with a ring of a uniform width . If O is the centre and 4 poles are fitted at A,B,C and Din a straight line then prove that AB=CD=1/2(AD-BC) meritnation experts plss send the ans fast coz 2morow I hve exam


Consider the question as two concentric circles with common centre O.Aline intersects these circles at points A,B,C,D.
To prove   AB=CD=12(AD-BC)
Construction   Draw OLAD

As we know that perpendicular from the centre of a circle to a chord bisects the chordNow since BC is a chord of the smaller circle and OLBC.BL=LC .............(1)Also AD is a chord of bigger circle and and OLADAL=LD...........(2)Subtracting (1)  from (2),we get     AL-BL=LD-LCAB=CD provedNow we can write      AB+BC+CD=AD ( from figure)AB+CD =AD-BCAB+AB = AD-BC  (as AB = CD)2AB= AD-BCAB=12 (AD-BC)And as AB=CDAB=CD=12 (AD-BC)    proved

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