A GRASSY PLOT IS 80M X 60M. 2 CROSS EACH 4M WIDE ARE BUILT SUCH THAT EACH IS PARALLEL TO ONE OF THE SIDES . FIND THE AREA OF THE PATH .

The figure below shows a grassy plot in which length of grassy plot, PQ = 80 m and breadth of grassy plot, QR = 60 m.
And two path each of width 4 m cross each other .

Now P'Q' = length of grassy plot = PQ = 80 m.
/so, area of path P'Q'R'S' = length of grassy plot $\times$ width of the path = 80 m $\times$ 4 m = $320 {\mathrm{m}}^2$
Again, A'D' = Width of grassy plot = 60 m
So, area of path A'B'C'D' = Width of grassy plot $\times$ width of the path = 60 m $\times$ 4 m = $240 {\mathrm{m}}^2$
Now we have a square LMNO is common to both the path.
And area of square LMNO = $4 \mathrm{m}\times 4 \mathrm{m} = 16 {\mathrm{m}}^2$

Then area of the path inside a grassy plot = area of path P'Q'R'S'  + area of path A'B'C'D' - area of square LMNO
= $320 {\mathrm{m}}^2+240 {\mathrm{m}}^2-16 {\mathrm{m}}^2 = 544 {\mathrm{m}}^2$