a hemispherical bowl of uniform thickness 1 cm and external diameter of 20 cm is full of water.water is emptied in a cylindrical vessel of internal diameter 12 cm.find the height of water level in the cylindrical vessel. Share with your friends Share 3 Neha Sethi answered this Given thickness =1 cmExternal diameter=20cmSo external radius=202=10cmWe know thatExternal radius= internal radius+thicknessSo, internal radius=External radius-thickness=10-1=9cmNow volume of hemisphere=23πr3=486πNow volume of cylinder=πr2h486π=πr2h volume of hemispher= volume of cylinder486=36hSo, h=13.5cm Regards 1 View Full Answer Bhargavi Subash answered this Hemisphere:-Thickness = 1 cmExternal diameter = 20 cmExternal radius = 20/2= 10cmInternal radius = 10-1 = 9 cm (as thickness = 1cm)Volume of hemisphere =2/3x 22/7x r3 = 2/3x 22/7 x 9 x 9 x 9Cylinder: - 3Diameter = 12cmRadius = 6 cmVolume of cylinder = 22/7x r2xh =22/7 x 6 x 6 x hVolume of hemisphere = volume of cylinder (as water is emptied)2/3 x 22/7 x 9 x 9 x 9 = 22/7 x 6 x 6 x h2/3 x 22/7 x 9 3 x 9 x 9 =22/7 x 6 x 6 x h2 x 3 x 9 x 9 = 6 x 6 x h2 x 3 x 9 3x 9/ 6 x 6 2 =h 3 x 9 / 2 =h h= 13.5 cm height of the water in the cylinder = 13.5 cm hope this will help you !!! thumbs up please if you like this !!! 8
