A large firm employes 1875 employees. One person is chosen at random, what is the probability that the persons birthday is on monday in the year 2007. If two persons are chosen in random what is the probability of having the birthday on monday of year 2007.

As there are 7 days in a week, so person having birthday on monday = 1/7
1) So when one person is chosen , then the probability = 1/7

2 ) Two persons have birthday on monday is independent event, So the probability of birthday on monday remains same for both of them.
Hence the probability = 1/7 * 1/7

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