A magnetic needle of negligible breadth and thickness compared to its length, oscillates in a horizontal plane witha period T. The period of oscillation of each part obtained on breaking the magnet into n equal parts perpendicularto the length is Share with your friends Share 5 Chetan Sharma answered this Dear student , regards 5 View Full Answer Vaishnavi Dhoble answered this The period of oscillation of each part obtained on breaking the magnet into n equal parts perpendicular to the length is T/n -13 Vishi answered this As s hip hole -8 Vishi answered this T = 2π√I/MB T' = 2π√I/n^3MB/n = 2π/n √I/MB T' =T/n -5 Anup Kulkarni answered this Please note that I is moment of inertia of the needle 1
