A man takes astep forward with probability 0.4 and backward with probability 0.6 find the the probability that at the end of eleven steps he is one step away from the starting point

Let a step forward be a success and a step backward be a failure.Then, the probability of success in one step=p=0.4=410=25And,  the probability of failure in one step=q=0.6=610=35In eleven steps he will be one step away from the starting point if the number of successes andfailures differ by 1.So, the number of successes=6, and the number of failures=5or the number of successes=5, and the number of failures=6Thus, the required probability=C611p6q5+C511p5q6=C611256355+C511255356=11!6!5!25535535+25=462×6255

  • 62
What are you looking for?