A manometer consists of a u-shaped tube containing a liquid. One side is connected to the appratus and other is open to the atnosphere. The pressure inside the appratus is then determined from the difference in heights of the liquid. The external pressure is 760 torr and density of liquid is 10gm cm^-3. The open side is 10.0 cm lower than the side connected to the appratus. The pressure in the appratus is (approx).
1)605.5 torr
2)685.5 torr
3)714.5 torr
4)720.1 torr
Dear student,
Here, density of oil, r = 10 g/cm3 = 104 kg/m3
Height, h = 10 cm = 0.1 m
Hence, the pressure exerted by 10 cm (0.1 m) liquid = r gh
= (104 kg/m3)(9.8m/s2)(0.1m)
= 9800 Pa
= 0.09674 atm
= 73.5224 torr
Therefore, pressure inside the apparatus = 760 - 73.5224
= 686.4776 (approx)
Regards
Here, density of oil, r = 10 g/cm3 = 104 kg/m3
Height, h = 10 cm = 0.1 m
Hence, the pressure exerted by 10 cm (0.1 m) liquid = r gh
= (104 kg/m3)(9.8m/s2)(0.1m)
= 9800 Pa
= 0.09674 atm
= 73.5224 torr
Therefore, pressure inside the apparatus = 760 - 73.5224
= 686.4776 (approx)
Regards