A metallic square loop ABCD of size 15 cm and resistance 1.0 Ω is moved at a uniform velocity of  v m/s, in a uniform magnetic field of 2 T, the field lines being normal to the plane of the paper. The loop is connected to an electrical network of resistors, each of resistance 2 Ω. Calculate the speed of the loop, for which 2 mA current flows in the loop.

Dear Student,
                      According to question i=VReq=vBlReqhere Req=1+(2+2)×(2+2)(2+2)+(2+2)=3ohm and l=.15mi=2Aso 2=v×2×.153v=20m/s
Regards

  • 1
What are you looking for?