) A mixture of CaCl2, and NaCl weighing 4.44 g is treated with sodium carbonate solution to precipitate all the calcium ions as calcium carbonate. The calcium carbonate so obtained is heated strongly to get 0.56 g of CaO. The percentage of NaCl in the mixture is [Atomic mass of Ca = 40]
W(cacl2)+W(nacl)=4.44g cacl2+na2co3 -caco3+2nacl 111g of cacl2 reacts with 106g of na2co3 to give 100g of caco3. 106g ofCaco3 on heating gives 56g of caO. 0.56g ofcaO is obtained from 1g of caco3 .. 111g of cacl2 gives 100g of caco3 .1g of caco3 is given by 1.11 g of cacl2 . 1.11g+W(nacl)=4.44g .w(nacl)=3.33g