A mixture of neon and argon at 250K has total KE 3kJ. the total mass of ne and ar is 30g.find the mass percentage of ne in the gaseous mixture Share with your friends Share 12 Vartika Jain answered this Dear Student, Let the mass of Ne be a and mass of Ar be bSo, a+b=30 ...(i)and, Molar mass of Ne =20 gMolar mass of Ar = 40 gSo, Moles of Ne+Moles of Ar= Total molesi.e. a20+b40= n Total kinetic energy, K.E.=32nRTHere, K.E. = 3kJ =3000 JT= 250 KR=8.314 JK-1mol-1Therefore, 3000 J=32( a20+b40)×8.314×2502a+b= 38.48 ...(ii)From eq. (i) and (ii), a =8.48 gand b = 21.52 gTherefore, mass % of Ne=mass of NeTotal mass×100=8.4830×100=28.2% 33 View Full Answer