A motor rated 25 HP(1 HP = 746 W) is used to pump water to the top of a building 0.1 km high. How long will it take to pump 80 tonne of water to the top ? ( Take g= 10 N/kg )

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Please find below the solution to the asked query:

$$\begin{gathered} 25 \text{HP} = 746\times 25=18650 \text{W} \\ \text{Height }h = 0.1 \text{Km}=100 \text{m} \\ \text{Mass} m=80 \text{tonne} = 80000 \text{Kg} \\ \text{Energy} E=mgh=80000\times 100\times 10=8\times {10}^7 \text{Jule} \\ \text{Time} t=\frac{E}{W}=\frac{8\times {10}^7}{18650}=4.28\times {10}^3 s=\text{1 hour 10.8 minute} \end{gathered}$$

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