a number is increased by 10% and then decreased by10% . find the increase or decrease percent.

Let the number be 100

Then increased number = 100 + 10% of 100 = 110

Then the number is decreased by 10%, so number = 110-10% of 110 = 110-11

= 99

So, decrease percent = 1%

- -1

Dear Ththteh,

Assume the number to be 100 for instance,

10% of 100 increased = 100 + ( 10/100*100 )

= 100 + 10 = 110

The resulting number decreased by its 10% = 110- (10/100*110)

= 110-11 = 99

Now, net decrease =100-99 = 1

Decrease percent = (Decrease / Original number * 100) %

= ( 1 / 100 *100 )%

= 1%.

Hope this helps...

Assume the number to be 100 for instance,

10% of 100 increased = 100 + ( 10/100*100 )

= 100 + 10 = 110

The resulting number decreased by its 10% = 110- (10/100*110)

= 110-11 = 99

Now, net decrease =100-99 = 1

Decrease percent = (Decrease / Original number * 100) %

= ( 1 / 100 *100 )%

= 1%.

Hope this helps...

- 8

Solution :-

Let the required number be 100.

Then, according to the question.

? Firstly,?the number is increased by 10 %

? 100 + (100?10)/100

? 100 + 10

= 110

Secondly, it is decreased by 10 %?

? 110 - (110?10)/100

? 110 - 11

? 99

Net increase or decrease percentage?

= (Original Number - New Number)?100/100

? (100 - 99)?100/100

? (1?100)/100

? 100/100

= 1 %

So, net decrease is 1 %

Let the required number be 100.

Then, according to the question.

? Firstly,?the number is increased by 10 %

? 100 + (100?10)/100

? 100 + 10

= 110

Secondly, it is decreased by 10 %?

? 110 - (110?10)/100

? 110 - 11

? 99

Net increase or decrease percentage?

= (Original Number - New Number)?100/100

? (100 - 99)?100/100

? (1?100)/100

? 100/100

= 1 %

So, net decrease is 1 %

- 0

**Assume the number to be 100 for instance,**

10% of 100 increased = 100 + ( 10/100*100 )

= 100 + 10 = 110

The resulting number decreased by its 10% = 110- (10/100*110)

= 110-11 = 99

Now, net decrease =100-99 = 1

Decrease percent = (Decrease / Original number * 100) %

= ( 1 / 100 *100 )%

= 1%

10% of 100 increased = 100 + ( 10/100*100 )

= 100 + 10 = 110

The resulting number decreased by its 10% = 110- (10/100*110)

= 110-11 = 99

Now, net decrease =100-99 = 1

Decrease percent = (Decrease / Original number * 100) %

= ( 1 / 100 *100 )%

= 1%

- 0

Dear Ththteh,

Assume the ?number to be 100 for instance,?

10% of 100 increased = 100 + ( 10/100*100 )

= 100 + 10 = 110

The resulting number decreased by its 10% = 110- (10/100*110)

= 110-11 = 99

Now, net decrease =100-99 = 1

Decrease percent = (Decrease / Original number * 100) %

= ( 1 / 100 *100 )%?

= 1%.

Hope this helps...

Assume the ?number to be 100 for instance,?

10% of 100 increased = 100 + ( 10/100*100 )

= 100 + 10 = 110

The resulting number decreased by its 10% = 110- (10/100*110)

= 110-11 = 99

Now, net decrease =100-99 = 1

Decrease percent = (Decrease / Original number * 100) %

= ( 1 / 100 *100 )%?

= 1%.

Hope this helps...

- 0

Dear Ththteh,

Assume the ?number to be 100 for instance,?

10% of 100 increased = 100 + ( 10/100*100 )

= 100 + 10 = 110

The resulting number decreased by its 10% = 110- (10/100*110)

= 110-11 = 99

Now, net decrease =100-99 = 1

Decrease percent = (Decrease / Original number * 100) %

= ( 1 / 100 *100 )%?

= 1%.

Hope this helps...

Assume the ?number to be 100 for instance,?

10% of 100 increased = 100 + ( 10/100*100 )

= 100 + 10 = 110

The resulting number decreased by its 10% = 110- (10/100*110)

= 110-11 = 99

Now, net decrease =100-99 = 1

Decrease percent = (Decrease / Original number * 100) %

= ( 1 / 100 *100 )%?

= 1%.

Hope this helps...

- 0