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a number is increased by 10% and then decreased by10% . find the increase or decrease percent.

Let the number be 100

Then increased number = 100 + 10% of 100 = 110

Then the number is decreased by 10%, so number = 110-10% of 110 = 110-11

= 99

So, decrease percent = 1%

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Dear Ththteh,
Assume the  number to be 100 for instance, 
10% of 100 increased = 100 + ( 10/100*100 )
= 100 + 10 = 110
The resulting number decreased by its 10% = 110- (10/100*110)
= 110-11 = 99
Now, net decrease =100-99 = 1
Decrease percent = (Decrease / Original number * 100) %
= ( 1 / 100 *100 )% 
= 1%.
Hope this helps...
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1% ans
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1%
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thanks
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1%
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Ans will be zera
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Let1st number be 100+10. Other number be 100-10. 110=90. 110-90=20
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1 % loss
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Here is answer

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Please find this answer

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A number is incressed by 10% and then decreased by 10%. Find the increase or decreased percent
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let the number be 100 then
=100{1+10/100}{1-10/100}
=100{110/100}{90/100}
=11*9
=99
100-99=1%loss
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Solution :-

Let the required number be 100.

Then, according to the question.

? Firstly,?the number is increased by 10 %

? 100 + (100?10)/100

? 100 + 10

= 110

Secondly, it is decreased by 10 %?

? 110 - (110?10)/100

? 110 - 11

? 99

Net increase or decrease percentage?

= (Original Number - New Number)?100/100

? (100 - 99)?100/100

? (1?100)/100

? 100/100

= 1 %

So, net decrease is 1 %
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Please find this answer

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100+10=110-10%=99
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4 percentage decrease
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1% decrease
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10 ? 10/100
100/100
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Assume the  number to be 100 for instance, 
10% of 100 increased = 100 + ( 10/100*100 )
= 100 + 10 = 110
The resulting number decreased by its 10% = 110- (10/100*110)
= 110-11 = 99
Now, net decrease =100-99 = 1
Decrease percent = (Decrease / Original number * 100) %
= ( 1 / 100 *100 )% 
= 1%
  • 0
Dear Ththteh,
Assume the ?number to be 100 for instance,?
10% of 100 increased = 100 + ( 10/100*100 )
= 100 + 10 = 110
The resulting number decreased by its 10% = 110- (10/100*110)
= 110-11 = 99
Now, net decrease =100-99 = 1
Decrease percent = (Decrease / Original number * 100) %
= ( 1 / 100 *100 )%?
= 1%.
Hope this helps...
  • 0
Please find this answer

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Answer is 0
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A trick for solving.. IF the no oF decrease and increase. Is same than,n2/100 (2=square ) =10 2/100 =1%
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it is a decrease by 1%
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Haha she should show she she z
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0% increase and 0%decrease. .
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Let the be 100
Increased by 10% = 100+10
=110
Deceased by 10%=110? 10\100
= 11
110-11
=99
Deceased percent =(110-99)%
=11%
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The formulla of this question is 10-10-(10?10?100)
10-10-1
-1
Decreased%
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let the number is 100

increase 10%=100+10=110

decrease of 10% on 110

=(10/100)?110=11

nett amount 110?11=99

So decrease 100?99=1

decrease of 1 out of 100

percentage of decrease 1%
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Let the number be 100
Therefore, number after 10% increase= 100+10=110
Decrease in the new number=10% of 110
=10?110/100=11
Final number= 110-11=99
Net decrease= 100-99=1
Hence, net decrease% = 1%
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0% because it is equal
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0 % because of equality
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Please find this answer

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The number will decrease by 1%
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Dear Ththteh,
Assume the ?number to be 100 for instance,?
10% of 100 increased = 100 + ( 10/100*100 )
= 100 + 10 = 110
The resulting number decreased by its 10% = 110- (10/100*110)
= 110-11 = 99
Now, net decrease =100-99 = 1
Decrease percent = (Decrease / Original number * 100) %
= ( 1 / 100 *100 )%?
= 1%.
Hope this helps...
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Please find this answer

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