a number of two digits exceeds four times the sum of its digits by 6 and it is increased by 9 on reversing the digits. find the number
here,
The two digit number is 34
To find:
Number = ?
Solution:
Given : A number of two digits exceeds four times the sum of its digit by 6 and it is increased by 9 on reversing the digits.
Assume the 1st digit number as a & Second digit number as b.
Hence, the two digit number = 10a + b
Number of two digits exceeds four times the sum of its digit by 6
10a + b = 4(a + b) + 6
10a + b = 4a + 4b + 6
6a - 3b = 6
2a - b = 2 ---------(1)
It is increased by 9 on reversing the digits.
10a + b + 9 = 10b + a
9a - 9b = -9
a - b = -1 ---------(2)
Solving the equations (1) & (2),
2a - b = 2
a - b = -1
a = 3
Replacing the value of a = 3 in 2a - b = 2
2(3) - b = 2
6 - b = 2
b = 4
Hence, the number = 10a + b
= 10(3) + 4
= 34
The two digit number is 34
To find:
Number = ?
Solution:
Given : A number of two digits exceeds four times the sum of its digit by 6 and it is increased by 9 on reversing the digits.
Assume the 1st digit number as a & Second digit number as b.
Hence, the two digit number = 10a + b
Number of two digits exceeds four times the sum of its digit by 6
10a + b = 4(a + b) + 6
10a + b = 4a + 4b + 6
6a - 3b = 6
2a - b = 2 ---------(1)
It is increased by 9 on reversing the digits.
10a + b + 9 = 10b + a
9a - 9b = -9
a - b = -1 ---------(2)
Solving the equations (1) & (2),
2a - b = 2
a - b = -1
a = 3
Replacing the value of a = 3 in 2a - b = 2
2(3) - b = 2
6 - b = 2
b = 4
Hence, the number = 10a + b
= 10(3) + 4
= 34