​A particle is moving on a straight line x+y=2. Its angular momentum about origin is L = 3t + 2. Find force acting on the particle at t=2s.

Dear student
  angular momentum = linear momentum ×lever arm lever arm = length of perpendicular online from origin =23t+2 =mv ×2differenciating both sides wrt to time3=mdvdt2F=32 N 
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  • 12
if we intigrate L,then force f= 3t2/2 +2t
                                        f=6+4
                                        f=10 N
  • -16
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