A particle is projected upward from the surface of earth(radius R) with a K.E. equal to half the minimum value needed for it to escape from earth's gravity. To what height does it rises above the surface of earth?

KE needed to escape from the surface:
           E=12mve2   =12m2Gmr2   =12m2Gmr   =GMmr

PE at the surface of Earth + 12E= PE at the maximum height
-GMmr+12GMmr=-GMmr+h-12GMmr=-GMmr+h              12r=1r+h               2r=r+h                h=r

Answer: h = r

  • 77
What are you looking for?