a particle moves along the x-axis according to the equation x=A sin(wt) find out the distance travelled by the particle during the time interval t=0 to t=t

Dear Student,

Please find below the solution to the asked query:

The displacement of the particle at any moment is given by the equation,

x=A sin ωt

But the distance travelled will be having different values,

If the 0<t<T/4, the distance travelled by the particle is x=A sin ωt.

If T/4 < t < T/2, the distance travelled by the particle is x'=A+A sin ωt

If T/2 < t < 3T/4, the distance travelled by the particle is x''=2A+A sin ωt

So, in this manner for every T/4 time interval, the distance travelled increases by A.

 

Hope this information will clear your doubts about the topic.

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Regards

  • 2
Hi Rutika Vittahl Marne, when t = 0 x = 0 and when t = t x = A sin wt
So distance traversed is got by the difference A sin wt - 0 = A sin wt
  • -2
 x gives displacement and not distance
  • 1
From question , dx /dt = Aw ( cos(wt))
At t=0, dx / dt = Aw
At t=t, dx/ dt = Aw [ cos(wt)] 
This gives ​Δt = t and Δv = Aw [ cos(wt)] - Aw = Aw [ cos(wt) - 1]
 = -2Aw [sin2(wt /2)]
Therefore, distance travelled  = ​Δt * ​Δv = -2Awt [sin2 (wt/2) ]
  • 0
d(t) *d (v)= d(s)=displacement i have asked displacement 
  • -1
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