a particle moves with a constant speed u along the curve y=sinx.the magnitude of its acceleration at the point corresponding to x=pi/2

y= sinx
dy/dx gives velocity
dy/dx = cosx
then d^2 y/dx^2 gives accleration
d^2y /dx^2 = -sinx
at x= pi/2
d^2y /dx^2 = -sin pi/2
             = -1
i.e a= -1 m/s^2
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correct.
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thnx a lot guys
 
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dy/dt gives velocity not dy/dx
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y= Sinx We have do derivatives on both sides We get the answer is u*2
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A particle moves with a constant speed u along the curve y = sin x. The magnitude of its acceleration at the point corresponding to x = π/2 is u22
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Please answer

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