​​a particle moving along a straight line has a velocity v m/s when it has cleared a distance of x m, these two are connected by the relation v= √(49+x). find acceleration of the particle when v = 1m/s 

Dear Student

a=dvdtv =dxdta=dxdt.dvdx=v .dvdxv =49+x1/2dvdx=1249+xa=v .dvdx=49+x1249+xa= 12When v = 1m/sa=v .dvdx=11249+xa =1249+x
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