A particle performs Simple harmonic motion of amplitude A along a straight line. When it is at a distance 31/2/2 A from mean position its kinetic energy gets increased by an amount 1/2 mw2A​2 due to an impulsive force. Then it's new amplitude becomes what?

Dear Student,

Please find below the solution to the asked query:

If the particle performs SHM with amplitude A along the straight line, than at any point the total energy should be,

If the additional kinetic energy of magnitude 12mω2A2 by means of an impulsive force, then the total energy of the particle changes to,

E'=E+12mω2A2=12mω2A2+12mω2A2 12mω2A'2=12mω22A2 A'2=2A2  A'=2A



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