a particle starts from rest ad moves a distance S1 with a constant acceleration in time T if this particle travel distance S2 in the next time t then show that s2=3s1
S 1 = ut + ½ at 2
u= 0
t= T
S 1 = ½ aT 2 …(1)
now
2aS 1 = v 2 –u 2
i.e 2 x a x ½ at 2 = v 2
or v= at … (2)
now when the particle travels the distance S2 again using equations of motion
S 2 = ut + ½ at 2
where now u= at {from euation (1)}
so S 2 = at + 1/at 2
or S 2 = 3/2 at 2 …..(3)
comparing equation (1) and (3)
S 2 = 3S 1