a particle starts from rest ad moves a distance S1 with a constant acceleration in time T if this particle travel distance S2 in the next time t then show that s2=3s1

S 1 = ut + ½ at 2

u= 0

t= T

S 1 = ½ aT 2 …(1)

now

2aS 1 = v 2 –u 2

i.e 2 x a x ½ at 2 = v 2

or v= at … (2)

now when the particle travels the distance S2 again using equations of motion

S 2 = ut + ½ at 2

where now u= at {from euation (1)}

so S = at + 1/at 2

or S 2 = 3/2 at 2 …..(3)

comparing equation (1) and (3)

S 2 = 3S 1


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S 1 = ut + ½ at 2 u= 0 t= T S 1 = ½ aT 2 …(1) now 2aS 1 = v 2 –u 2 i.e 2 x a x ½ at 2 = v 2 or v= at … (2) now when the particle travels the distance S2 again using equations of motion S 2 = ut + ½ at 2 where now u= at {from euation (1)} so S 2 = at + 1/at 2 or S 2 = 3/2 at 2 …..(3) comparing equation (1) and (3) S 2 = 3S 1
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