a person of normal eye sight can read a print at such a distance that the letters subtend an angle of 5' at the eye. find the height of the letters if he can read at a distance of 420 meters.

urgent solution required


Let the height of the letters be h m

Now in APQ we havetan PAQ =PQAQtan 5° =h420 h = tan 5°×420 = 0.087×420 m =36.54 m

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