a person standing at the foot of a tower walks 3a meters away from it and observes the angle of elevation to be alpha.He then walks a distance 4a perpendicular to the previous direction and observes the angle to be beta,then find the height of the tower in terms of beta?






Here AB is the tower and initially person is at A now he wals 3a to reach C and from there he will reach at D to cover a distance 4a and here visualizationis required as he will travell in horizontal direction so angle DAB will be 90 degreeNow in right angle triangle ACD, AD=CD2+AC2=9a2+16a2=5aNow angle ACB is α and angle ADB is β.So in right angle triangle ADB, tanβ=ABAD=AB5aAB = 5a tanβSo height of tower = AB=  5a tanβ unit.

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