A photon & electron having the same De Broglie wavelength .Which of them moves fast & posses more Kinetic energy .Justify

Solution
K.E. =12p2mp=2mKλ =hp =h2mKp =hλK=h22mλ2If λ is constant then p is constantmpvp =meveAsvpve=memp <  1So vp < veAlso if λ is constantK α 1mTherefore KpKe=memp <  1SoKp <Ke

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