A photon & electron having the same De Broglie wavelength .Which of them moves fast & posses more Kinetic energy .Justify Share with your friends Share 0 Vipra Mishra answered this Solution K.E. =12p2mp=2mKλ =hp =h2mKp =hλK=h22mλ2If λ is constant then p is constantmpvp =meveAsvpve=memp < 1So vp < veAlso if λ is constantK α 1mTherefore KpKe=memp < 1SoKp <Ke 0 View Full Answer