A piece of wood weighs 10 g in air .When a heavy piece of metal is suspended below it , the metal being submerged in water. The weight of wood in air plus metal in water is 14 g .the weight when both the wood and metal are submerged in water is 2 g. Find the volume and density of wood.

(i AM NOT ABLE TO SOLVE THE QUESTION AT ALL IS THERE SOME MISSING DATA)

Given that: mass of the wood in air = 10 g or 0.010 kg

Consider the situation when the combine weight of wood in air and metal in water is given : 

weight of wood in air + metal in water = 14 g or 0.014 kg

  0.010g + (m_ig - B_i) = 0.014g ------------(1), where m_i is the mass of the metal piece and  B_i is the buoyancy  force acting in upward direction due to metal piece.  

Consider the situation when weight of both the wood and metal are submerged in water together:

 weight of wood in water + metal in water = 2 g or 0.002 kg

 (0.010g - B_w) + (m_ig - B_i) = 0.002g  --------------(2),where B_w is the buoyancy  force acting in upward direction due to wood.

 solving above two equations we'll get:

   B_w = 0.012g 

  V ρ g = 0.012g 

 ⇒ Volume of the water displaced =  

 = 1.2 × 10^-5 m³ 

As,  Volume of the wooden block = Volume of the water displaced

 ∴ Volume of the wooden block = 1.2 × 10^-5 m³

Now we have got one part of the question and since density of the wooden block can also be find easily with with the below mentioned formula:

 Density of the wooden block =