A proton is moving with velocity 104 m/s parallel to the magnetic field of intensity 5 tesla. The force on the proton is - | ||
(a) | 8 × 10–15 N | |
(b) | 104 N | |
(c) | 1.6 × 10–19 N | |
(d) | Zero |
Hello!
The force exerted (FB) by the magnetic field (of strength B) on a moving charged particle (having velocity v and mass m) is given as
where θ is the angle between the velocity vector and magnetic field.
In this case, the electron is moving parallel to the direction of the magnetic field, thus θ = 90o.
So, the force becomes
or the force exerted would be zero.
option (d) is the right answer.
Hello @Shashank! good job with the answer, keep it going!