A proton is moving with velocity 104 m/s parallel  to the magnetic field of intensity 5 tesla. The force on the proton is - 

(a)

8 × 10–15 N

(b)

104 N

(c)

1.6 × 10–19 N

(d)

Zero

Hello!

The force exerted (FB) by the magnetic field (of strength B) on a moving charged particle (having velocity v and mass m) is given as

 

where θ is the angle between the velocity vector and magnetic field.

In this case, the electron is moving parallel to the direction of the magnetic field, thus θ = 90o.

So, the force becomes

 

or the force exerted would be zero.

option (d) is the right answer.

 

Hello @Shashank! good job with the answer, keep it going!

  • 13

 Zero

  • 3
thanx
  • -1
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