A SHORT CONDUCTOR OF LENGTH 5 cm IS PLACED PARALLEL TO A LONG CONDUCTOR OF LENGTH 1.5m NEAR ITS CENTRE.THE CONDUCTOR CARRY CURRENT 4.0A AND 5.0A RESPECTIVELY IN SAME DIRECTION .WHAT IS TOTAL FORCE EXPERIENCED BY LONG CONDUCTOR WHEN THEY ARE 3.0 cm APART ?

current in short one is 4A and in long is 3Afield at long conductor due to short conductor .B=4μ02π0.03force on the long  conductor F=4μ02π0.03*3*1.5=10-7*8*150=1.2*10-4 N Regards

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