A small square loop of wire of side l is placed inside a large square loop of side L. The loops are coplanar and their centres coincide. The mutul inductance of the system is proportional to (a) l /L. (b) l^2/L

Dear Student,

Magnetic Field at the centre of outer square current(I) carrying loop is

B1=22μ0IπL

Since L>>l we approximate the magnetic field through entire inner coil by B1
Thus the flux through inner coil

φ21=B1A2=22μ0Iπ×l2L

Mutual Inductance = φ21I1

or, M= 22μ0π×l2Lor, M= const×l2Lor, Ml2L

option(2) CORRECT ANSWER

Regards.
 

  • 66
Hello Pradeep dear, the option l^2 / L is the right one
  • -28
What are you looking for?