A solution of oxalic acid (COOH)2.2H2O is prepared by dissolving 0.63 gm of acid in 250 ml of solution calculate molarity of the solution.
Molar mass of oxalic acid = 126.1g
No. of moles of solute = 0.63g / 126.1g = 0.005 mol
Since molarity ( M ) = No. of moles of solute / Volume of solution in litres
= 0.005mol / 0.25L = 0.02M
THus the molarity of the solution is 0.02M
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