a sum of rs 10000 was borrowed on first march and repaid on 25th july of the same year at a interest rate on 5.5% of interest . what was the interest paid???

Answer :

Given :

Principle amount P  =  Rs . 10000

Rate of interest r =  5.5%

Time t  = 1^st march to 25^th july = total days  =  31 + 30 + 31 + 30 +25 = 147 , So

Time t in years  = $\frac{147}{365}$

And we know
Simple interest = $\frac{P \times r \times t }{100}$
So,
Total interest paid = $\frac{10000 \times 5.5\times {\displaystyle \frac{147}{365}}}{100} = \frac{10000 \times 5.5\times {\displaystyle 147}}{100 \times 365} = \frac{8085000}{36500} =$ Rs. 221.50  ( Ans )