A transformer has 250 primary turns and 500 secondary turns.If 200V electric potential is applied to the primary turns resulting in a current of 5 mA, find the secondary voltage and current
Ip/Is=Ns/Np=Es/Ep Ip=primary current
Np=250 Is=secondary current
Ns=500 Ns=no. Of turns for secondary
Therefore, Ns/Np=2 Np=no. Of turns for primary
Ep=200 (gn) Es=emf of secondary
Es/Ep=Ns/Np=2 Ep=emf of primary
Therefore, Es/200=2
Es=400V
Ip/Is=Ns/Np=2
Therefore,Ip/Is=2
Ip=5mA=5*10^(-3)A
5mA/Is=2
Therefore,Is=2.5mA