A uniform electric field E of 300N/C is directed along PQ. A(4,1) , B(4,4) and C(-3,4) are three points in the field having X and Y(in metres). Calculate potential difference between the points i)A and B ii)B and C Share with your friends Share 12 Vara answered this (i)Distance between A and B:d=4-42+4-12 =3 mPotential difference:V=Ed =300 × 3 =900 volts(ii)Distance between A and B:d=-3-42+4-42 =7 mPotential difference:V=Ed =300 × 7 =2100 volts 22 View Full Answer