​​a wire is (7x-3) metres long.a length of (3x-4)meter is cut for use now ans the question
if this left out wire is used for making an equilateral triangle what is the lengthof each side of the triangle so formed

Total length of the wire = 7x-3 mtsLength of the wire that is cut = 3x-4 mLength of the wire left = 7x-3 - 3x-4 = 7x-3-3x+4 = 4x+1 mNow, perimeter of equilateral  = 4x+1 m3s =  4x+1     where s = length of each side of an equilateral s = 4x+13 mLength of each side of an equilateral  =4x+13 m 

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de
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Hello Ramandeep, initial length = 7 x - 3
Length cut out = 3 x - 4
So left out length = 7 x - 3 -( 3x - 4) = 7 x - 3 - 3x + 4 = 4x + 1
Now as equilateral triangle of length a is formed with this length 4x + 1
then a = 1/3 * (4x + 1) = 4/3 * x + 1/3
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