ab and cd are two equal chords ofa circle with centre o.op and oq are perpendiculars on chords ab and cd respectively.if angle poq=100, find pqd?

Here angle POQ = 100 degree
And AB and CD are equal chord so OP=OQ hence angle OQP= angle OPQ so
In triangle OPQ , 
OPQ+OQP+100=180OPQ=OQP=40Hence angle PQD = 90 +40 = 130 degree

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