ABC & BDE are two equilateral triangle such that D is the midpoint of BC. If AE intersects BC at F,show that:
1) ar(BDE)= 1/4 ar(ABC)
2) ar(BDE)= 1/2 ar(BAE)
​3) ar(ABC)= 2 ar(BEC)
4) ar(BFE)=  ar(AFD)
5) ar(BFE)= 2ar(FED)
6) ar(FED)= 1/8 ar(AFC)
(Hints: Join EC & AD. Show that BE parallel to AC and DE parallel to AB,etc.)

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