ABC is a right angled triangle in which A(0,2) and B(2,0) are given. Then coordinates of C are :

1. (0,0)

2. (2,2)

3.(1,1)

4.(-2,-2)

If your question is
ABC is a right angled isosceles triangle in which A(0,2) and B(2,0) are given. Then coordinates of C are :
Sol:
GivenA(0,2) and B(2,0)Let Co-ordinates of C(x,y)Given ABC is a isosceles triangleAC=BC(x-0)2+y-22=x-22+y-02Squaring on both sidesx2+y-22=x-22+y2x2+y2-4y+4=x2-4x+4+y2x=yABC is a right triangleAB2=AC2+BC2(2-0)2+0-222=(x-0)2+y-222+x-22+y-02282=x2+(x-2)2+(x-2)2+x28=4x2-8x+84x(x-2)=0x=0,2and y=0,2So,Co-ordinates of C(0,0) or C(2,2)

 

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