ABC is a triangle in which AB=AC. P is any point in the interior of the triangle such that angle ABP=ACP.prove that APbisects angle BAC

Given: ABC is a triangle in which AB=AC. P is any point in the interior of the triangle such that angle ABP=ACP.

To Prove: AP bisects angle BAC

Proof: 

In  tr. APB and tr. APC,

AB = AC [given]

angle ABP = angle ACP [given]

AP = AP [common]

also, 

angle PAB = angle PAC [corresponding angles of congruent triangles]

thus, AP bisects angle BAC.

hence proved.

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