ABCD is a rhombus,EABF is a straight line such that EA = AB = BF prove that ED and - Maths - Quadrilaterals

Question

ABCD is a rhombus,EABF is a straight line such that EA = AB = BF
prove that ED and FC when produced meet at right angles

Aakash Sharma · Accepted Answer

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ABCD is a rhombus,EABF is a straight line such that EA = AB = BF. prove that ED and FC when produced meet at right angles.