ABCD is a square M is the midpoint of AB and CM perpendicular to PQ as shown in the - Maths - Areas of Parallelograms and Triangles

Question

ABCD is a square M is the midpoint of AB and CM perpendicular to PQ
as shown in the figure Show that CP=CQ
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Varun.Rawat · Accepted Answer

In ∆PAM and ∆QBM,∠PAM = ∠QBM   90° each     AM = MB         As M is the mid point of AB∠AMP = ∠QMB    Vertically opposite angles⇒∆PAM≅∆QBM   ASA⇒PM = QM    CPCTIn ∆CPM and ∆CQM,CM = CM   common∠CMP = ∠CMQ   90° eachPM = QM    proved above∆CPM ≅ ∆CQM    SAS⇒CP = CQ    CPCT

ABCD is a square. M is the midpoint of AB and CM perpendicular to PQ as shown in the figure. Show that CP=CQ ​

ABCD is a square. M is the midpoint of AB and CM perpendicular to PQ as shown in the figure. Show that CP=CQ