ABCD is acyclic quadrilateral in which AD is parallel to BC if the bisector of angle A meets BC - Maths -

Question

ABCD is acyclic quadrilateral in which AD is parallel to BC if
the bisector of angle A meets BC at point E and the given circle at
point F, prove that:
(i) EF= FC
(ii) BF = DF

Shubham Chourasiya · Accepted Answer

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ABCD is acyclic quadrilateral in which AD is parallel to BC. if the bisector of angle A meets BC at point E and the given circle at point F, prove that: (i) EF= FC (ii) BF = DF

ABCD is acyclic quadrilateral in which AD is parallel to BC. if the bisector of angle A meets BC at point E and the given circle at point F, prove that:

(i) EF= FC

(ii) BF = DF