AD is the median of Triangle ABC on base BC If angleADC=90degree prove that Triangle ABC is isosceles - Maths - Congruence of Triangles

Question

AD is the median of Triangle ABC on base BC If angleADC=90degree
prove that Triangle ABC is isosceles

ramandeep.singh · Accepted Answer

In Î”ADB and Î”ADC BD =CD (Median AD bisects BC) âˆ ADB = âˆ ADC = 900 AD = AD (Common side) âˆ´Î”ADB $≅$ Î”ADC (Using SAS rule) â‡’AB = AC Therefore, Î”ABC is isosceles

AD is the median of Triangle ABC on base BC. If angleADC=90degree prove that Triangle ABC is isosceles.