Ahmed and Afzal win a jar containing 500 sweets in a competition They divide the sweets in the ratio - Maths - Ratio and Proportion

Question

Ahmed and Afzal win a jar containing 500 sweets in a competition
They divide
the sweets in the ratio 3 : 7 Ahmed shares his in the ratio 3 : 2
with his wife and
Afzal shares his is the ratio 3 : 4 with his girlfriend
How many sweets do Ahmed and Afzal have each?

Neha Sethi · Accepted Answer

Dear student
Total sweets in jar=500Let the common ratio=xAlso, 3x+7x=50010x=500x=50Total sweets with Ahmed=3×50=150Total sweets with Afjal=7×50=350No
of sweets that Ahmed shared with his wife=23+2×150=60No
of sweets that Afjal shared with his girlfriend=43+4×350=200So, No
of sweets now Ahmed have=150-60=90No
of sweets now Afjal have=350-200=150

Regards

Ahmed and Afzal win a jar containing 500 sweets in a competition. They divide the sweets in the ratio 3 : 7. Ahmed shares his in the ratio 3 : 2 with his wife and Afzal shares his is the ratio 3 : 4 with his girlfriend. How many sweets do Ahmed and Afzal have each?

Ahmed and Afzal win a jar containing 500 sweets in a competition. They divide
the sweets in the ratio 3 : 7. Ahmed shares his in the ratio 3 : 2 with his wife and
Afzal shares his is the ratio 3 : 4 with his girlfriend.
How many sweets do Ahmed and Afzal have each?