al satellite moving in a circular orbit around the Earth has a total (K.E. + P.E.) = E₀. Its potential energy is:

• A )

  E₀

• B )

  1.5 E₀

• C )

  2 E₀

• D )

  E₀

Potential energy of satellite (U)= $\frac{-GMm}{r}$
It is because of gravitational pull acting on satellite due to the earth. Here M= mass of earth, m= mass of satellite,r= radius of orbit.
Kinetic energy of satellite = $\frac{m{v}^2}{2}$
                                     =$\frac{m}{2}\left(\frac{Gm}{r}\right)$        as v= $\sqrt{\frac{Gm}{r}}$   where v is the orbital velocity of the satellite.
Then, total energy of the satellite=  K.E.+P.E.

                                               ε₀ = $\frac{-GMm}{2r}$
Therefore potential energy= 2ε_0. So correct option is (c).