all tha jacks, queen and kings are removed from a deck of 52 playing cards. the remaining cards are well shuffled and then one card is drawn ramdomly. giving ace a value 1 similar value for other cards, find the probability that card has a value
1) 7 2) greater than 7 3) less than 7
Removing the required cards will leave 40 cards .
52 - ( 3 x 4) = 40 cards ( 4 each of jack , queen and king)
P( 7) = Number of event / sample space = 4 / 40 = 1/10
P(>7) = 3x4 cards (card numbered 8 , 9 and 10 and 4 set of each ) = 12 cards
therefore probability = 12 /40 or 3 by 10
p(<7) = 4 x 6 cards i.e. 24 cards probability = Number of event / sample space = 24 / 40 = 3 / 5
Hope this would have cleared your doubt.
52 - ( 3 x 4) = 40 cards ( 4 each of jack , queen and king)
P( 7) = Number of event / sample space = 4 / 40 = 1/10
P(>7) = 3x4 cards (card numbered 8 , 9 and 10 and 4 set of each ) = 12 cards
therefore probability = 12 /40 or 3 by 10
p(<7) = 4 x 6 cards i.e. 24 cards probability = Number of event / sample space = 24 / 40 = 3 / 5
Hope this would have cleared your doubt.