an AC circuit is given by L C R given

Dear student,
We have, XL=90Ω, XC=30Ω and R=R1+R2=44+36=80Ω Impedance , Z=R2+(XLXC)2=(80)2+(60)2= Z=6400+3600 = 100Ω I=VZ=200100=2A Pav=I2R=(2)2×36=144W

Option 3 is correct

Regards

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