An AP starts with a positive fraction and every alternate term is an integer. If the sum of the first 11 terms is 33, then find the 4th term Share with your friends Share 6 Lovina Kansal answered this Dear student We know thatSn=n22a+n-1dSo,S11=1122a+11-1d33=1122a+10d6611=2a+10d2a+10d=6a+5d=3 ... 1Since every alternate term is an integer and given sum is positivea+3d=2 ...2Subtracting 2 and 12d=1d=12a=2-32a=4-32a=12So, a4=a+3d=12+3×12=12+32=42=2 Regards -6 View Full Answer