an electric immersion heater of 1.08 kW is immersed in water.After the water has reached a temperature of 100 C, how much time will be required to produce 100g of stream? Share with your friends Share 16 Ravi Gupta answered this The heat energy required to liquid water at a temperature of 100°C to steam is equal to the latent heat of vaporization of water 2260×103 J/kg. The heat energy required to liquid water at a temperature of 1000C to 100g of steam = 226 × 103 J. power of the immersion heater = 1.08×103 W, electrical energy consumed = Power × Time ⇒ Time = electrical energy consumed/ Power =226 × 103 1.08×103 = 209 s 61 View Full Answer
