an electron in a hydrogen like species is in the excited state (n2) the wavelengths corresponding to a transition - Chemistry - Structure of Atom

Question

an electron in a hydrogen like species is in the excited state (n2)
the wavelengths corresponding to a transition second orbit is 48
24nm and from same orbit, wavelength corresponding to a transition
to third orbit is 142 46 nm find n2 and Z(atomic number)

Shruti Srivastava · Accepted Answer

Dear â€‹Samiksha
Jain,

1λ=RHZ2 [1n12-1n22]if n1 = 2; λ=48
24 nm    n2 = 3; λ=142
46 nm148 24=RHZ2 [14-1n22]----11142
46=RHZ2 [19-1n22]----2divide equation 1 by equation 2142
4648 24=n22-4n22-9×941
31 =n22-4n22-9; n2 = 5 place the value of n2 in euation 1RH = 109677 cm-1; λ= 48
24 ×10-7 cm148
24×10-7=109677 × Z2 [14-125]Z = 3n2 = 5 and Z = 3
Regards

an electron in a hydrogen like species is in the excited state (n2). the wavelengths corresponding to a transition second orbit is 48.24nm and from same orbit, wavelength corresponding to a transition to third orbit is 142.46 nm. find n2 and Z(atomic number)