An elevator descends into a mine shaft at the rate of 6m/min .If the descent starts from 10m above ground level, how long will it take to reach -350 m .

elevator is 10m above the ground level.

it has to reach -350m.

so total vertical distance is =10+ 350=360

speed is 6m/min

so it will take =360/6=60 mins or 1 hour to cover the distance

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